铅酸蓄电池放电时的化学反应方程式为( )
(A)PbO2+ 2H2SO4→PbSO4+2H2O
(B)PbSO4 +2H2O→PbO2 +2H2S04
(C)PbO2+Pb+2H2SO4→2PbSO4+2H2O
(D)2PbSO4 +2H2O→PbO2 +Pb+2H2S04
参考答案
继续答题:下一题
(A)PbO2+ 2H2SO4→PbSO4+2H2O
(B)PbSO4 +2H2O→PbO2 +2H2S04
(C)PbO2+Pb+2H2SO4→2PbSO4+2H2O
(D)2PbSO4 +2H2O→PbO2 +Pb+2H2S04